节选自:安卓-连续点击两次返回键退出程序-二级界面的退出程序
法一:实现方式,通过记录按键时间计算时间差实现:
import android.app.Activity;
import android.os.Bundle;
import android.view.KeyEvent;
import android.widget.Toast;
public class MainActivity extends Activity {
private long exitTime = 0;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if (keyCode == KeyEvent.KEYCODE_BACK) {
exit();
return false;
}
return super.onKeyDown(keyCode, event);
}
public void exit() {
if ((System.currentTimeMillis() - exitTime) > 2000) {
Toast.makeText(getContext(), "再按一次退出程序", Toast.LENGTH_SHORT).show();
exitTime = System.currentTimeMillis();
} else {
finish();
System.exit(0);
}
}
}